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Thanks Avula - basic mistake !
Tried it, it worked :--)) Marrow on the MS newsgroup pointed out quite rightly the processor is applying the default rules for any elements without templates (and of course these don't have strip-space LOL)
So - Thanks for the pointers Avula & all, I think I'm having one of those days :-p
One interesting thing I may need to do : Transform one or more of my elements to quoted-printable encoding. What this means is : substitute carriage returns in the original source -element- with the string =0D=0A=
I looked briefly at translate() function, but that only translates one character into another, where I need to translate one character into a string.
Now, will I run into problems with the default processing of XML where line endings are normalised, I *think* to a newline (if correct ?) That is, my XSL never gets to see the carriage return characters ? If so, I need to do some pre-processing in PHP before passing to my stylesheet.
Suggestions / URLs gratefully received
At 14:40 07/04/2003 -0400, you wrote:
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
RE: [xsl] Strip space in Sablotron (Non-Problem : fixed ;-)
Subject: RE: [xsl] Strip space in Sablotron (Non-Problem : fixed ;-) From: Neil Smith <neil@xxxxxxxxxxxxxxx> Date: Tue, 08 Apr 2003 15:52:02 +0100 |
Thanks Avula - basic mistake !
Tried it, it worked :--)) Marrow on the MS newsgroup pointed out quite rightly the processor is applying the default rules for any elements without templates (and of course these don't have strip-space LOL)
So - Thanks for the pointers Avula & all, I think I'm having one of those days :-p
One interesting thing I may need to do : Transform one or more of my elements to quoted-printable encoding. What this means is : substitute carriage returns in the original source -element- with the string =0D=0A=
I looked briefly at translate() function, but that only translates one character into another, where I need to translate one character into a string.
Now, will I run into problems with the default processing of XML where line endings are normalised, I *think* to a newline (if correct ?) That is, my XSL never gets to see the carriage return characters ? If so, I need to do some pre-processing in PHP before passing to my stylesheet.
Suggestions / URLs gratefully received
Cheers, Neil Smith.
At 14:40 07/04/2003 -0400, you wrote:
Date: Mon, 7 Apr 2003 11:06:27 -0700
From: "Avula, Raj" <ravula@xxxxxxxxxxx>
Subject: RE: [xsl] Strip space in Sablotron keeps unwanted (source XML) li ne breaks :-(
If you start your xsl with the root level element it should solve the problem.
<xsl:template match="/iCalendar"> <xsl:apply-templates select="vcalendar/vevent" /> </xsl:template>
<xsl:template match="vevent".............
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