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[xsl] Replacing DTD reference with xsd reference
Subject: [xsl] Replacing DTD reference with xsd reference From: Cams Ismael <Ismael.Cams@xxxxxxxxxxx> Date: Wed, 2 Apr 2003 09:39:21 +0200 |
Hello all, can somebody provide me some help with the following. I have thousands of files that conform to a DTD. Now I have written a schema for these files. Therefore a transformation is needed for all the files. So I have: <?xml version="1.0"?> <!DOCTYPE trap SYSTEM "./trap.dtd"> <trap> .... </trap> The result should be: <?xml version="1.0"?> <trap xmlns="mynamespace.uri" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="mynamespace.uri trap.xsd"> .... </trap> Because copy-of select copies also the namespace, this is not an option for me (because I want to transform from no namespace into mynamespace.uri). Is there a good way to do this with XSLT, or should I better use a script for transforming my xml files ? Kind regards, Ismaël XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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