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Re: [xsl] generate full xpath name to an attribute?

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    yikes! - looks like the simplest way is to have:

    <xsl:template match="name">
        <xsl:for-each select="ancestor-of-self::*">
          <xsl:value-of select="name()" /><xsl:text>/</xsl:text>
        </xsl:for-each>
        <xsl:value-of select="." />
      </xsl:template>

depending on your document type this might not give you an unambigous
path back to your attribute (and you probably want a @ before that last
step)

eg
<x>
  <a id="a1"/>
  <a id="a2"/>
</x>

both id attributes would get a path of /x/a/id from the above code.

David

  

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