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Re: [xsl] use of xsl:key in cross-referencing

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Dear Wendell:

  Thank you for your reply.  Your solution could have
solved my problem as well, the essence is similar to
Lars' soltuion which is if creating a key with the
same name using two different groups that key off
different elements, then I need to use different match
pattern for the two different groups.  The difference
is your solution separated the groups by cell, and
Lars solution used row.

Thanks for the help, much appreciated.
Xiaocun

--- Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> wrote:
> Xiaocun,
> 
> Sorry I've been off the list-- out here in the hills
> of WV, my phone line 
> is down, and I have to hoof it to my neighbor's to
> get a net connection.
> 
> Anyhow, you are pretty close to your solution:
> 
> <xsl:key name="QuestionnaireKey"
>   match="row[count(cell)=3]/cell[2]"
>   use="."/>
> 
> <xsl:key name="QuestionnaireKey"
>   match="row[count(cell)=2]/cell[1]"
>   use="."/>
> 
> Instead of recognizing the different groups by their
> row number, I decided 
> to use the count of their cells. If I have three
> cells, I know this is a 
> row like
> 
> <row row="17">
>    <cell column="1">Questionnaire B</cell>
>    <cell column="2">QB</cell>
>    <cell column="3">Questionnaire B, empty with no
> questions</cell>
> </row>
> 
> and the Questionnaire identifier is the second cell
> (whose value is 'QB').
> 
> If I have only two cells, however, my data is like
> this
> 
> <row row="28">
>    <cell column="1">QA</cell>
>    <cell column="2">Questionnaire A, Question
> 2</cell>
> </row>
> 
> and the identifier is the first cell (value is
> 'QA').
> 
> If this assumption does not hold for your data, you
> need to adjust the 
> match patterns in the key declarations to whatever
> does work.
> 
> On the data as you provided it, the Questionnaire
> key retrieves either one 
> of these kinds of identifiers by the correct value
> ('QA', 'QB' or 'QC').
> 
> Then if I have
> 
> <xsl:template match="/">
>    <xsl:apply-templates
>      select="//cell[key('QuestionnaireKey',.) and
>                    
> count(.|key('QuestionnaireKey',.)[1])=1 ]"/>
> </xsl:template>
> 
> I select
> 
> //cell   ... all the cells in the document...
> 
> [key('QuestionnaireKey',.)
> ... testing whether this cell's value is among my
> Questionnaire identifiers 
> (note this introduces a very subtle assumption about
> these identifiers, 
> namely that they are unique strings) ...
> 
> and count(.|key('QuestionnaireKey',.)[1])=1 ]
> ... making sure if it is an identifier, it's the
> first one (Muenchian 
> grouping).
> 
> I think you can see this is a cleaned-up version of
> what you almost had....
> 
> Cheers,
> Wendell
> 
> At 06:36 PM 3/20/2003, you wrote:
> >Hi, Wendell:
> >
> >Thanks for the idea of define two keys for the two
> >groups with the same name but different "use"
> value,
> >but I was unable to find anything in regard to it
> at
> >Jenni's website, xsl-list archive (using keywords
> "two
> >key;same name;") or google web/group.  I did some
> >thinking myself and still don't see how that works.
> >Following is an example, having rows 10-19 being
> the
> >first group (Questionnaire) and 20-29 being the
> second
> >group (Question):
> ><range>
> ><row row="16">
> >         <cell column="1">Questionnaire A</cell>
> >         <cell column="2">QA</cell>
> >         <cell column="3">Questionnaire A, two
> >questions</cell>
> ></row>
> ><row row="17">
> >         <cell column="1">Questionnaire B</cell>
> >         <cell column="2">QB</cell>
> >         <cell column="3">Questionnaire B, empty
> with no
> >questions</cell>
> ></row>
> >
> ><row row="27">
> >         <cell column="1">QA</cell>
> >         <cell column="2">Questionnaire A, Question
> 1<cell>
> ></row>
> ><row row="28">
> >         <cell column="1">QA</cell>
> >         <cell column="2">Questionnaire A, Question
> 2</cell>
> ></row>
> ><row row="29">
> >         <cell column="1">QC</cell>
> >         <cell column="2">Questionnaire C, Question
> 1</cell>
> ></row>
> ></range>
> >
> >In this case, questionnaire QA has two questions,
> QB
> >is only referred in the 1st group and QC is only
> >referred in the 2nd group.  What I need is to be
> able
> >to process each of QA/QB/QC.
> >
> >To define two keys for the two groups with the same
> >name but different "use":
> ><xsl:key name="QuestionnaireKey" match=//row[@row
> &lt;
> >20]" use="string(cell[@column=2])"/>
> ><xsl:key name="QuestionnaireKey" match=//row[@row
> &gt;
> >20]" use="string(cell[@column=1])"/>
> >
> >Use Muenchian method to process each just once, for
> >the 2nd group:
> ><xsl:apply-templates select="//row[@row &gt; 20 and
> >@row &lt; 30][count(.|key('QuestionnaireKey',
> >string(cell[@column=1]))[1]) = 1]"/>
> >but this will miss questionnaire QC.
> >
> >I guess to take advantage of the combined key, I
> need
> >to do select on all rows, like:
> ><xsl:apply-templates
> >select="//row[count(.|key('QuestionnaireKey',
> >string(cell[@column=1]))[1]) = 1]"/>
> >Would the above work?  If so, how can I tell if the
> >row being processed is from group 1 (Questionnaire)
> or
> >2 (Question)?
> 
>
___&&__&_&___&_&__&&&__&_&__&__&&____&&_&___&__&_&&_____&__&__&&_____&_&&_
>      "Thus I make my own use of the telegraph,
> without consulting
>       the directors, like the sparrows, which I
> perceive use it
>       extensively for a perch." -- Thoreau
> 
> 
>  XSL-List info and archive: 
> http://www.mulberrytech.com/xsl/xsl-list
> 


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