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Re: [xsl] bug in LibXSLT???

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Not quite but this works:

    <xsl:for-each select="ancestor-or-self::*[@name]">
      <xsl:text>/</xsl:text>
      <xsl:value-of select="@name"/>
    </xsl:for-each>

(there's ancestors without a @name)

thanks.

simon

On Friday, March 7, 2003, at 04:45 AM, Jre@xxxxxxxxxxxx wrote:

This is a problem with the line
        <xsl:for-each select="ancestor-or-self::*/@name">
If you change this to
        <xsl:for-each select="ancestor-or-self::*">
and then change
        <xsl:value-of select="."/>
to
        <xsl:value-of select="@name"/>
you'll get the ordering you want (and expect!).

Daniel: I've logged this in bugzilla: 107804 (but you probably already
know that by now).

John Escott.

XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list

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