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[xsl] indenting identity
Subject: [xsl] indenting identity From: Carl Yu <carl.yu@xxxxxxxxxxxx> Date: Thu, 16 Jan 2003 14:26:00 -0800 (PST) |
Why does... <?xml version="1.0"?> <xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="xml" indent="yes"/> <!-- IDENTITY copy, using nodes --> <xsl:template match="node()|@*"> <xsl:copy> <xsl:apply-templates select="node()|@*" /> </xsl:copy> </xsl:template> indent and <?xml version="1.0"?> <xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="xml" indent="yes"/> <!-- IDENTITY copy, using elements --> <xsl:template match="*|@*"> <xsl:copy> <xsl:apply-templates select="*|@*" /> </xsl:copy> </xsl:template> not? I know that one is a node and the other is an element... but is there a way to maintain indentation when copying elements? Carl XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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