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RE: [xsl] How do can I select distinct nodes and adding a counter at the sa me time
Subject: RE: [xsl] How do can I select distinct nodes and adding a counter at the sa me time From: Cams Ismael <Ismael.Cams@xxxxxxxxxxxxxxx> Date: Fri, 22 Nov 2002 16:21:34 +0100 |
Hello Tom, first thanks for trying to help. I know what you mean, but the problem I have is how do I produce a tree with distinct values that I can access afterwards. What I do know is first sorting, so all the same values are together. Than I check every time with the preceding value, when this values are different I write the node to the output. But when I now want to use the position function I have the problem that the nodes that are double are also count. Sending the stylesheet is difficult because it's more complicated than the examples I have sent, and I am afraid it would make everything a little bit confusing. The only thing I actually need is storing a copy of my tree with distinct values that I can access afterwards. But is seems not as easy as putting it in a variable. All ideas are welcome ! Kind regards, Ismaël -----Original Message----- From: TSchutzerWeissmann@xxxxxxxxxxxxxxxx [mailto:TSchutzerWeissmann@xxxxxxxxxxxxxxxx] Sent: vrijdag 22 november 2002 12:33 To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: RE: [xsl] How do can I select distinct nodes and adding a counter at the sa me time Hi Ismaël > What I do know is first grouping on the attributes, so I get > every value > only once. Therefore I have used the sorting function. The > problem is I > don't find a method to generate the id. I can't use the count function > because some nodes of the nodeset are not used (only unique values are > needed). Somebody an idea ? If you're apply-templates to the distinct nodes, or running over them with a for-each, then you should be able to use position() in either case. What does your xslt look like? Regards, Tom XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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