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Robin,
At 09:41 AM 11/21/2002, you wrote:
Well, since attributes never have children you could say
select=" *[1]//*[not(*)] | *[1]//@*]"
which is a *little* easier.
It gets leaf node descendants of the first child element, plus all attributes on the first child or its descendants. Is this what you want? If you want only attributes on the leaf nodes that'll be "*[1]//*[not(*)] | *[1]//*[not(*)/@*", but in that case I'd think it'd be better first to select the leaves, then in a template get their attributes.
You can exclude nodes that have an F ancestor by grouping with () and qualifying the group with another predicate:
select="(*[1]//*[not(*)] | *[1]//@*)[not(ancestor::F)]"
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Re: [xsl] Exclusions in XPATH
Subject: Re: [xsl] Exclusions in XPATH From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> Date: Thu, 21 Nov 2002 11:14:43 -0500 |
Robin,
At 09:41 AM 11/21/2002, you wrote:
XPATH help appreciated !
XML: <A> <B> <C>101</C> <D> <E W="XYZ">0204268270</E> <F> <G>Versicherungsstr. 1</G> <H>Offenburg</H> </F> </E> </D> </B> </A>
XSL: <xsl:template match="A"> <xsl:for-each select="./*[1]//*[not(*)]|./*[1]//@*[not(*)]"> <xsl:value-of select="name()"/> <xsl:if test="position()!=last()">;</xsl:if>
</xsl:for-each> <xsl:apply-templates/> </xsl:template>
This gives me output of: C;E;W;G;H
Question 1: Can I get both attribute-names and element-names more easily in the select or does it have to be like I have it above ?
Well, since attributes never have children you could say
select=" *[1]//*[not(*)] | *[1]//@*]"
which is a *little* easier.
It gets leaf node descendants of the first child element, plus all attributes on the first child or its descendants. Is this what you want? If you want only attributes on the leaf nodes that'll be "*[1]//*[not(*)] | *[1]//*[not(*)/@*", but in that case I'd think it'd be better first to select the leaves, then in a template get their attributes.
Question 2: How can I exclude the descendants of element F from the select ? Output would then be C;E;W. I've tried various combinations but either end up with all-or-nothing.
You can exclude nodes that have an F ancestor by grouping with () and qualifying the group with another predicate:
select="(*[1]//*[not(*)] | *[1]//@*)[not(ancestor::F)]"
Cheers, Wendell
___&&__&_&___&_&__&&&__&_&__&__&&____&&_&___&__&_&&_____&__&__&&_____&_&&_ "Thus I make my own use of the telegraph, without consulting the directors, like the sparrows, which I perceive use it extensively for a perch." -- Thoreau
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