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Juan Carlos Gonzalez wrote:
J.Pietschmann
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Re: [xsl] Node Concatenation
Subject: Re: [xsl] Node Concatenation From: "J.Pietschmann" <j3322ptm@xxxxxxxx> Date: Mon, 04 Nov 2002 21:45:31 +0100 |
Juan Carlos Gonzalez wrote:
Hi:
I'm trying to accomplish the following in a dropdown list box:
Accesories - Batteries Accesories - Cables Accesories - FireWire Products Accesories - FireWire Products - Hubs Accesories - FireWire Products - Interface Accesories - Headsets Digital Digital - Cameras ...etc...
This is my xml file:
<root> <cat id=1 name="Accesories"> <cat id=2 name="Batteries"/> <cat id=2 name="Cables"/> <cat id=3 name="FireWire Products"> <cat id=4 name="Hubs"/> <cat id=5 name="Interface"/> </cat> <cat id=6 name="Headsets"/> </cat> <cat id=7 name="Digital"> <cat id=8 name="Cameras"/> </cat> </root>
Walk the ancestor axis: <xsl:template match="cat"> <xsl:for-each select="(ancestor::cat)"> <xsl:sort select="."/> <!-- may be unnecessary --> <xsl:value-of select="@name"> <xsl:if test="position()!=last()"> <xsl:text> - </xsl:text> </xsl:if> </xsl:for-each> <xsl:apply-templates/> </xsl:template> (Untested, watchout for unwanted whitespace, LF etc.)
J.Pietschmann
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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