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Deepak,
At 11:29 AM 11/1/2002, I wrote:
Of course the simpler solution to this (doh!) is:
or the analogous logic. Then you need no logic in the B template.
Incidentally, this can be further compressed (if you like) as:
<xsl:template match="Y"/> <!-- this suppresses a Y unless it matches the other template -->
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RE: [xsl] Delete XML Node
Subject: RE: [xsl] Delete XML Node From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> Date: Fri, 01 Nov 2002 11:39:15 -0500 |
Deepak,
At 11:29 AM 11/1/2002, I wrote:
Or more simply, if a Y will never have more than one B, you can do
<xsl:template match="B"> <B1> <xsl:apply-templates/> </B1> </xsl:template>
This allows your rule (finding that you need a Y since you have a B='ABC') to be in one place, which is better; the down side is that if you have input like
<Y> <B>ABC</B> <B>LMN</B> <C>zzz</C> <Y>
And your rules are only in the Y template, since "B[.='ABC'] or C[.='XYZ']" is true, all B and C elements will be processed.
Of course the simpler solution to this (doh!) is:
<xsl:template match="Y"> <xsl:if test="B[.='ABC'] or C[.='XYZ']"> <Y1> <xsl:apply-templates select="B[.='ABC'] | C[.='XYZ']"/> </Y1> </xsl:if> </xsl:template>
or the analogous logic. Then you need no logic in the B template.
Incidentally, this can be further compressed (if you like) as:
<xsl:template match="Y[B[.='ABC'] or C[.='XYZ']]"> <Y1> <xsl:apply-templates select="B[.='ABC'] | C[.='XYZ']"/> </Y1> </xsl:template>
<xsl:template match="Y"/> <!-- this suppresses a Y unless it matches the other template -->
Cheers, Wendell
====================================================================== Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx Mulberry Technologies, Inc. http://www.mulberrytech.com 17 West Jefferson Street Direct Phone: 301/315-9635 Suite 207 Phone: 301/315-9631 Rockville, MD 20850 Fax: 301/315-8285 ---------------------------------------------------------------------- Mulberry Technologies: A Consultancy Specializing in SGML and XML ======================================================================
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