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Di Dion,
thanks for your help. It works fine :-)
Dion Houston wrote:
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Re: [xsl] Select a node by name
Subject: Re: [xsl] Select a node by name From: Andreas Schlegel <schlegel@xxxxxxxxxxxxxxxxxxx> Date: Sat, 05 Oct 2002 12:21:35 +0200 |
Di Dion,
thanks for your help. It works fine :-)
Greetings, Andreas
Dion Houston wrote:
Hi Andreas:
There's actually a couple issues here...
The select issue is actually pretty easy and straight forward. To
select the person element who has a name attribute of Betty, simply use
the XPath:
/persons/person[@name="Betty"]
The second issue is that xsl:value-of outputs the text content of the node you specify. So in the case of:
<xsl:value-of select="/persons/person[@name='Betty']"/>
This will actually display nothing. Why? In your sample XML below, the person _element_ has no text content.
If what you're looking for is (for example) the job, then use the following:
<xsl:value-of select="/persons/person[@name='Betty']/@job"/>
HTH!
Dion
-----Original Message-----
From: Andreas Schlegel [mailto:schlegel@xxxxxxxxxxxxxxxxxxx] Sent: Friday, October 04, 2002 3:26 PM
To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] Select a node by name
Hi,
writing a XSL file I have the problem to get a specific node of the list.
Having a XML file like this:
<persons> <person name="Bill" job="Developer"/> <person name="Steve" job="Admin"/> <person name="Betty" job="CEO"/> </persons>
A statement like <xsl:value-of select="person"/> won't help because I have a lot of nodes of the type PERSON.
If I have a node already selected I may use <xsl:value-of select="@name"/>
It's no problem to do it by for each ( <xsl:for-each select="person"> ).
But I look for a way to pick a person out of the list, i.e. "Betty".
Any ideas?
Greetings, Andreas
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