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[xsl] RE: replace &lt; and &gt; with < and >

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--- "bryan" <bry at itnisk dot com> wrote:
> RE: replace &lt; and &gt; with < and >
> From: "bryan" <bry at itnisk dot com> 
> To: <xsl-list at lists dot mulberrytech dot com> 
> Date: Fri, 20 Sep 2002 12:10:32 +0200 
> Subject: RE: [xsl] replace &lt; and &gt; with < and > 
> Reply-to: xsl-list at lists dot mulberrytech dot com 
> 
>
--------------------------------------------------------------------------------
> 
> >> The xml file is returned from a method is in a string format, 
> >> and the xml 
> >> file seems to encode all < and > using &lt; and &gt;. So, 
> >> what I need to do 
> >> is to convert that xml file from a string to a xml nodelist 
> >> so I can access 
> >> all the elements.
> 
> >No, you need to correct the program that is generating the XML so
> that
> >it does it properly.
> 
> Funny enough I'm dealing with the same problem, the problem in my
> case
> is caused by msxml's screwy philosophy of extension functions, i.e
> that
> the function can only return text, thus if you have an extension
> function that returns an rtf, for example if you wrote an improved
> document() with some decent error handling you're screwed cause your
> xml
> is gonna be text with a lot of &lt;&gt;.
> 
> So basically one can do the following <xsl:value-of
> select="myfunc:func('http://www.example.com/example.xml')"
> disable-output-escaping="yes"/> to get the xml out of the extension
> function. Can one then do the following:
> <xsl:variable name="nodeset"><result><xsl:value-of
> select="myfunc:func('http://www.example.com/example.xml')"
> disable-output-escaping="yes"/> </result></xsl:variable>
> 
> <xsl:apply-templates select="msxsl:node-set($nodeset)/result"/>?
> 
> nope. 
> 
> If I want the xml processed, or you want the xml processed as far as
> I
> have found, I suppose one will have to do the processing inside the
> extension function, by perhaps loading in myfunc_func.xsl and
> processing
> that xml inside the extension function, returning an rtf to the
> function
> which then converts the whole thing to text and then going ahead and
> converting it back to xml via <xsl:value-of
> select="myfunc:func('http://www.example.com/example.xml')"
> disable-output-escaping="yes"/>.
> 
> Anyway this is what I was thinking about doing to solve my particular
> problem, if I still feel like solving it, not sure if it's worth it.
> 
> By the way, If anyone else has a better solution for getting an rtf
> out
> of an msxml extension function please tell me.

Hi Bryan,

It is extremely easy to return a ***regular node-set*** from an
extension function of MSXML3/4. I am not aware of any way to "return an
RTF" from an extension function. By definition, an RTF is always
created by the XSLT processor -- not from extension functions.

For an example of an extension function returning a node-set, do have a
look at the VB source code of the XSL Calculator, described at:

"An XSL Calculator: The Math Modules of FXSL"

http://fxsl.sourceforge.net/articles/xslCalculator/The%20FXSL%20Calculator.html#6._Putting_it_All_Together_-_the_XSLT_Calculator

The dispResult() method of the extension object I'm using there is
returning a node-set -- the xml representation of a request for
performing a calculation. It is defined in the following way:


Public Function dispResult(strResult As Variant) As IXMLDOMNodeList

Dim strArg1 As String, strXML As String

Dim xmldoc As New MSXML2.FreeThreadedDOMDocument40

Dim strOp As String

frmCalc.txtUser = strResult

frmCalc.Show vbModal

strOp = frmCalc.strOp

strXML = "<calc><op>" & strOp & "</op>" & _

"<arg>" & frmCalc.strArg1 & "</arg>" & _

"<arg>" & frmCalc.strArg2 & "</arg></calc>"

xmldoc.loadXML strXML

Set dispResult = xmldoc.selectNodes("/")

End Function


In the stylesheet, which calls this method, no further conversion is
necessary -- it just uses the returned node-set as node-set.


Hope this helped.



=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL

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