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Subject: RE: [xsl] <xsl:apply-templates select="not('nodename')"/> ? From: "Américo Albuquerque" <aalbuquerque@xxxxxxxxxxxxxxxx> Date: Tue, 27 Aug 2002 16:25:07 +0100 |
Hi Michael! your third apply-templates is selecting a boolean value (not(...)). you need to change your xpath to select nodes something like: <xsl:apply-templates select="*[not(name()='apple' or name()='orange')]"/> hope that this helps you -----Original Message----- From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of Michael Rothwell Sent: Tuesday, August 27, 2002 4:02 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] <xsl:apply-templates select="not('nodename')"/> ? I would like to preferentially list some children ahead of others. I'm trying to do it like this: <xsl:apply-templates select="./apple"/> <xsl:apply-templates select="./orange"/> <xsl:apply-templates select="not(apple|orange)"/> ... I want for the third line to process all other children. It's not working that way though. What's the right syntax to achieve this? Thanks, -M XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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