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RE: [xsl] transforming lists

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Hi,

Just call me stupid, but could you show what the output should be? I mean what should the def attribute mean and translate to?

> Is it possible to transform an input like the following to 
> get back a list
> with bullets for XSL:fo?
> ( the fo list users sent me here, cause it's a general XSLT 
> problem ...)
> 
> <pardef id="9" leftmargin="1.2500in" list="bullet"/>
> 
>    <par def="9">
>     <run>
>      <font size="11pt" name="serif"/>ITEM 1 liste</run>
>    </par>
> 
>    <par>
>     <run>
>      <font size="11pt" name="serif"/>ITEM 2 liste</run>
>    </par>
> 
>    <par>
>     <run>
>      <font size="11pt" name="serif"/>ITEM 3 liste</run>
>     <run>
>      <font size="11pt" style="bold" name="Arial" color="blue"/>
>      <break/>
>     </run>
>    </par>
> 
> 
> My problem is, that the <par> elements 2,3 don't contain a 
> def attribute for
> referencing - only
> the first one does..

Cheers,

Jarno

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