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RE: [xsl] transforming lists
Subject: RE: [xsl] transforming lists From: Jarno.Elovirta@xxxxxxxxx Date: Wed, 24 Jul 2002 14:59:20 +0300 |
Hi, Just call me stupid, but could you show what the output should be? I mean what should the def attribute mean and translate to? > Is it possible to transform an input like the following to > get back a list > with bullets for XSL:fo? > ( the fo list users sent me here, cause it's a general XSLT > problem ...) > > <pardef id="9" leftmargin="1.2500in" list="bullet"/> > > <par def="9"> > <run> > <font size="11pt" name="serif"/>ITEM 1 liste</run> > </par> > > <par> > <run> > <font size="11pt" name="serif"/>ITEM 2 liste</run> > </par> > > <par> > <run> > <font size="11pt" name="serif"/>ITEM 3 liste</run> > <run> > <font size="11pt" style="bold" name="Arial" color="blue"/> > <break/> > </run> > </par> > > > My problem is, that the <par> elements 2,3 don't contain a > def attribute for > referencing - only > the first one does.. Cheers, Jarno XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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