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nrashidi wrote:
Hi Nick,
you only must find the way or XPath from SEC to T. Write this XPath in the paranthesis: generate-id(any/valid/XPath).
Regards,
Joerg
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Re: [xsl] generate-id() question
Subject: Re: [xsl] generate-id() question From: Joerg Heinicke <joerg.heinicke@xxxxxx> Date: Mon, 03 Jun 2002 21:26:24 +0200 |
nrashidi wrote:
Novice question...
I need to create links and i need the output of template match T to correspond to the ID values that are used in the href. I am not sure what needs to be put for the node-set argument of generate-id().
<xsl:for-each select="SEC"> <a href="#{generate-id()}">
Hi Nick,
you only must find the way or XPath from SEC to T. Write this XPath in the paranthesis: generate-id(any/valid/XPath).
Regards,
Joerg
<xsl:value-of select="."/> </a> <xsl:text/> <xsl:value-of select="following-sibling::*[1]"/><br/> </xsl:for-each> </xsl:template>
<xsl:template match="T"> <a name="{generate-id()}"><xsl:value-of select="."/></a><br/> </xsl:template>
Thanks Nick
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