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[xsl] how to output elements in random order?
Subject: [xsl] how to output elements in random order? From: Massimo Santini - mailing list address <mm14ss@xxxxxxxx> Date: Thu, 31 Jan 2002 22:18:51 +0100 (CET) |
Is there a standard (clean) way to process (output) elements in random order, possibliy specifiyng a "seed" as a parameter to the stylesheet? It's not just a speculation. One motivation, for example, is that I'm tryng to use XSLT to produce randomly premuted multiple choice tests for grading students. Given a set of questions each one with a various number of possible answers, I wuold like to output questions in random order and answers within a quastion in random order too. Now I'm basically using something like <xsl:for-each select="question"> <xsl:sort select="ext:rnd()"/> ... </xsl:for-each> where ext:rnd() is an extension function returing a random integer. It works with Xalan, but I know it is an ugly ugly hack... Is there any clean way to do such a thing (note that STFW seems to lead no useful result)? Thank you for any suggestion... Massimo > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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