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RE: [xsl] How to get a value from other node
Subject: RE: [xsl] How to get a value from other node From: "stevenson" <stevenson@xxxxxxxxxxxxxxxxxxxxxx> Date: Thu, 31 Jan 2002 11:15:46 +0300 |
am not quite sure why you are doing a tes. Anyway i would do something like this: <xsl:value-of select="MyXml/content/city/address" /> -----Original Message----- From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Aleksander Bracko Sent: 31 January 2002 10:56 To: 'XSL-List@xxxxxxxxxxxxxxxxxxxxxx' Subject: [xsl] How to get a value from other node I have following XML: <MyXml> <header> <location> Home </location> </header> <content> <city name = "city1"> <address> Address1 </address> </city> <city name = "city2"> <address> Address2 </address> </city> </content> </MyXml> My XSL looks like this: <?xml version="1.0"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/TR/WD-xsl"> <xsl:template match="/"> <xsl:apply-templates /> </xsl:template> <xsl:template match="header"> <MyHome> <xsl:value-of select="location"/> <------ After this I want to insert another value from other node (address) </MyHome> <xsl:apply-templates /> </xsl:template> </xsl:stylesheet> And now my problem is: I would like to insert another value, but from other node. I thought that i could use a line like this one, but it doesn't work <xsl:if test="../content/city@name[.='city2']"> <xsl:value-of select="../content/city/address" /> </xsl:if> If u could please help me out. Thanx, Alex XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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