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Re: [xsl] for-each order
Subject: Re: [xsl] for-each order From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> Date: Fri, 14 Dec 2001 17:12:43 +0000 |
Hi Charly, > Is there a way to do <xsl:for-each ..... and looping backwards. Sure. Sort (numerically) on position() in descending order: <xsl:for-each select="histo/bar"> <xsl:sort select="position()" order="descending" data-type="number" /> <xsl:value-of select="@value" /> <xsl:if test="position() != last()">,</xsl:if> </xsl:for-each> Note that the call to position() in the select attribute of the xsl:sort looks at the order of the selected nodes in the document, whereas the call to position() within the xsl:for-each looks at the sorted order of the nodes as they're being processed. I hope that helps, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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