[XSL-LIST Mailing List Archive Home] [By Thread] [By Date]

Re: [xsl] arguments for xsl:call-template

---

---

[Pep Coll]

> I don't understand quite well what you want, because you can do this:
>     <xsl:with-param name="path" select="'/report/histo/bar'" />
> but you can do this ,
>     <xsl:with-param name="path" select="'/report/histo/@bar'" />

NO, @bar would only return attributes named "bar" and the original example
had "bar" elements, not attributes.

Tom P

> because you are not assigning anything to var. path and also you are doing
> histogram just once so the 'for-each' has no reason to be. Explain what's
> the purpose of this template.
>



 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

---