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I replaced the "if" statements (that tested the passed-in column parameter) in my stylesheet with the suggested XSL:
The column title links now sort the table, but there are two problems:
1)Using XML containing data for 11 loans, the Search Results page displays loans 1 - 10 in the table. All of the data for the 11th loan is displayed above the table. I can't determine which part of my XSL is causing this loan data to be erroneously displayed.
The data is being displayed above the table as:
9823410-Mar-2001 New 10-Nov-1999 Max Lyons 23492 Jen Masters L 1 Josh Masters P 2 300 S. State St. 140000.0 TRUE 7.10 13-Aug-2000
When I click the "Next Page" or "Last Page" link, the eleventh loan is displayed in the table, and all of the data for the first ten loans is displayed above the table.
2)When I click a column title link to sort the loans, only the 10 loans being displayed on the page are sorted. When I click the "Next Page" link, the eleventh loan is displayed, despite the fact that the Borrower's last name is "Masters" and therefore the loan should have been displayed as the fourth loan when the table is sorted by "Last Name".
Any suggestions?
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Re: [xsl] Paging and Sorting
Subject: Re: [xsl] Paging and Sorting From: "Katie McNally" <kmcnally9@xxxxxxxxxxx> Date: Thu, 18 Oct 2001 15:03:31 -0500 |
I replaced the "if" statements (that tested the passed-in column parameter) in my stylesheet with the suggested XSL:
<xsl:apply-templates select="ReturnResultSet/LoanSearchSet/Loan"> <xsl:sort select="LoanId[$column = 'LoanId'] | LoanBorrowerSet[$column = 'LastName'] /Borrower/LastName" /> </xsl:apply-templates>
The column title links now sort the table, but there are two problems:
1)Using XML containing data for 11 loans, the Search Results page displays loans 1 - 10 in the table. All of the data for the 11th loan is displayed above the table. I can't determine which part of my XSL is causing this loan data to be erroneously displayed.
The data is being displayed above the table as:
9823410-Mar-2001 New 10-Nov-1999 Max Lyons 23492 Jen Masters L 1 Josh Masters P 2 300 S. State St. 140000.0 TRUE 7.10 13-Aug-2000
When I click the "Next Page" or "Last Page" link, the eleventh loan is displayed in the table, and all of the data for the first ten loans is displayed above the table.
2)When I click a column title link to sort the loans, only the 10 loans being displayed on the page are sorted. When I click the "Next Page" link, the eleventh loan is displayed, despite the fact that the Borrower's last name is "Masters" and therefore the loan should have been displayed as the fourth loan when the table is sorted by "Last Name".
Any suggestions?
Thanks, Katie
From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> Reply-To: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> To: "Katie McNally" <kmcnally9@xxxxxxxxxxx> CC: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] Paging and Sorting Date: Thu, 18 Oct 2001 16:19:23 +0100
Hi Katie,
> I have the paging functionality working, but not the sorting. What > do I need to do to do to include sorting cababilities when the user > clicks on a column link? My XSL and XML are below.
What you've got at the moment is:
> <xsl:if test="$column='LoanId'">
> <xsl:apply-templates select="ReturnResultSet/LoanSearchSet">
> <xsl:sort select="ReturnResultSet/LoanSearchSet/Loan/LoanId"
> order="ascending"/>
> </xsl:apply-templates>
> </xsl:if>
> <xsl:if test="$column='LastName'">
> <xsl:apply-templates select="ReturnResultSet/LoanSearchSet">
> <xsl:sort
> select="ReturnResultSet/LoanSearchSet/Loan/LoanBorrowerSet/Borrower/LastName"
> order="ascending"/>
> </xsl:apply-templates>
> </xsl:if>
The reason this isn't working is that the select attribute of xsl:sort is evaluated relative to the nodes that are selected by the surrounding xsl:apply-templates/xsl:for-each. At the moment, the paths are looking for the 'ReturnResultSet' children of the 'LoanSearchSet' nodes that are being sorted.
I think what you actually want to do is sort the Loans against the LastName or LoanId, in which case you need to apply templates to the Loan elements, as follows:
<xsl:choose> <xsl:when test="$column = 'LoanId'"> <xsl:apply-templates select="ReturnResultSet/LoanSearchSet/Loan"> <xsl:sort select="LoanId" /> </xsl:apply-templates> </xsl:when> <xsl:when test="$column = 'LastName'"> <xsl:apply-templates select="ReturnResultSet/LoanSearchSet/Loan"> <xsl:sort select="LoanBorrowerSet/Borrower/LastName" /> </xsl:apply-templates> </xsl:when> </xsl:choose>
Alternatively, you could use the following trick:
<xsl:apply-templates select="ReturnResultSet/LoanSearchSet/Loan"> <xsl:sort select="LoanId[$column = 'LoanId'] | LoanBorrowerSet[$column = 'LastName'] /Borrower/LastName" /> </xsl:apply-templates>
If $column is 'LastName' then the LoanId element will be selected, but the LoanBorrowerSet won't be, so you'll end up sorting by the value of the LoanId element. On the other hand, if the $column is 'LastName', then the LoanId element won't be selected but the LoanBorrowerSet/Borrower/LastName element will be, so you'll end up sorting by last name.
Another thing I'll just mention is that you're making very strange use of attribute value templates. You only need to put {}s around expressions in attributes that you want to be evaluated dynamically and inserted into the attribute value. If you're adding a static string to the attribute value, then there's no need to use an attribute value template. For example, instead of:
> <a
> href="/loans/SearchResults.jsp?{'sort='}{$column}{'&upperLimit='}{$upperLimit}{'&action=First'}{'&counter='}{$counter}">
> <b>First Page</b></a>
You could more simply have:
<a
href="/loans/SearchResults.jsp?sort={$column}&upperLimit={$upperLimit}&action=First&counter={$counter}">
<b>First Page</b></a>
I hope that helps,
Jeni
--- Jeni Tennison http://www.jenitennison.com/
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