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RE: [xsl] Finding the maximum number of nodes (Redux)
Subject: RE: [xsl] Finding the maximum number of nodes (Redux) From: "McKeever, Marty" <marty.mckeever@xxxxxxxxxxxxxxxxx> Date: Wed, 03 Oct 2001 11:06:26 -0400 |
of the two, i certainly prefer your solution. It is much simpler to write and understand. but as a mental exercise (something to do on my lunch break), i wanted to see if i could create a single XPath statement that would do the job. I nearly bit off more than i could chew! Now that it "works", i'm just wondering if anyone can verify the logic behind it. I'm still not certain that I even understand "why" it works... Thanks for the code tho -- good stuff. Marty > -----Original Message----- > From: Jörg Heinicke [mailto:joerg.heinicke@xxxxxx] > Sent: Wednesday, October 03, 2001 10:35 AM > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: Re: [xsl] Finding the maximum number of nodes (Redux) > > > > <xsl:attribute name="colspan"><xsl:value-of > select="count(tr[count(td) > > > > count(following-sibling::tr[count(td) > > > count(preceding-sibling::tr[last()]/td)]/td)][count(td) > > > count(preceding-sibling::tr[last()]/td)]/td)"/></xsl:attribute> > > This would be unacceptable for me - who should understand that later? > > Why not something like that: > > <xsl:template match="table"> > <xsl:variable name="cols"> > <xsl:for-each select="tr"> > <xsl:sort select="count(td)"/> > <xsl:if test="position()=last()"> > <xsl:value-of select="count(td)"/> > </xsl:if> > </xsl:for-each> > </xsl:variable> > <table border="1"> > <tr> > <td colspan="{$cols}">Table Header Text</td> > </tr> > <xsl:copy-of select="tr"/> > </table> > </xsl:template> > > Joerg > > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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