[XSL-LIST Mailing List Archive Home] [By Thread] [By Date]

RE: [xsl] how to group equal nodes by a it's position()

---

---

thanks Paul. It does what I want.

> -----Original Message-----
> From: Paul Tyson [mailto:paul@xxxxxxxxxxxxxxxxxxxxxx]
> Sent: Friday, September 28, 2001 10:45 PM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re: [xsl] how to group equal nodes by a it's position()
> 
> 
> Dmitri,
> 
> This does, literally, what you asked for.
> 
> If you want HTML-like tables with rows and cells, you'd use 
> <table> literal
> result elements (instead of <table_n>), and add some template 
> processing of
> <call> elements (instead of copy-of).  One way of making 
> table rows from a
> list is shown in archived post:
>      
> http://www.biglist.com/lists/xsl-list/archives/200109/msg01324.html
> 
> <xsl:template match="calls">
>     <xsl:call-template name="make-tables"/>
> </xsl:template>
> 
> <xsl:template name="make-tables">
>     <xsl:param name="nth-item" select="1"/>
>     <xsl:param name="table-number" select="1"/>
>     <xsl:variable name="table-name"
> select="concat('table_',$table-number)"/>
>     <xsl:choose>
>         <xsl:when test="$nth-item &gt; count(call)"/><!-- done -->
>         <xsl:when test="$nth-item = 1">
>             <!-- the first table, 10 items -->
>             <xsl:element name="{$table-name}">
>                 <xsl:copy-of select="call[position() &lt;= 10]"/>
>             </xsl:element>
>             <xsl:call-template name="make-tables">
>                 <xsl:with-param name="nth-item" 
> select="$nth-item + 10"/>
>                 <xsl:with-param name="table-number" 
> select="$table-number +
> 1"/>
>             </xsl:call-template>
>         </xsl:when>
>         <xsl:when test="count(call) - $nth-item &lt; 20">
>             <!-- the last table, up to 20 items -->
>             <xsl:element name="{$table-name}">
>                 <xsl:copy-of select="call[position() &gt;= 
> $nth-item]"/>
>             </xsl:element>
>         </xsl:when>
>         <xsl:otherwise>
>             <xsl:element name="{$table-name}">
>                 <xsl:copy-of select="call[position() &gt;= 
> $nth-item and
>                          position() &lt; $nth-item + 15]"/>
>             </xsl:element>
>             <xsl:call-template name="make-tables">
>                 <xsl:with-param name="nth-item" 
> select="$nth-item + 15"/>
>                 <xsl:with-param name="table-number" 
> select="$table-number +
> 1"/>
>             </xsl:call-template>
>         </xsl:otherwise>
>      </xsl:choose>
>   </xsl:template>
> 
> Have fun,
> Paul
> 
> ----- Original Message -----
> From: "Dmitri Ilyin" <dmitri.ilyin@xxxxxxxxx>
> To: "XSL-List@lists. mulberrytech. com (E-mail)"
> <XSL-List@xxxxxxxxxxxxxxxxxxxxxx>
> Sent: Friday, September 28, 2001 12:15 PM
> Subject: [xsl] how to group equal nodes by a it's position()
> 
> 
> > Hi *,
> >
> > i have next xml:
> >
> > <calls>
> >  <call>sme text</call>
> >  <call>sme text</call>
> >  <call>sme text</call>
> >  <call>sme text</call>
> >  <call>sme text</call>
> >  <call>sme text</call>
> >  <call>sme text</call>
> >  <call>sme text</call>
> >  <call>sme text</call>
> >  <call>sme text</call>
> >  .....
> >  <call>sme text</call>
> > </calls>
> >
> > i have to group the <call> by it's position()
> > to get
> > <table_1>
> >  <call>some text</call>
> >  from position 1 to 10 (10 elements in the table_1)
> >  <call>some text</call>
> > </table_1>
> > <table_2>
> >  <call>some text</call>
> >   from position 11 to 25 (15 elements in table_2)
> > </table_2>
> > ....
> > <table_n>
> >  <call>some text</call>
> >   from position 26 to 40 (15 elements in table_n)
> > </table_n>
> >
> > <table_x>
> >  <call>some text</call>
> >   from position nnn to mmm (20 elements or less in table_x)
> > </table_x>
> >
> > So I have 3 types of tables, with 10, 15, 20 elements.
> > The number of call nodes in table 1 must be 10 and it must 
> be first 10
> > elements,
> > the number of call nodes in tables 2 to n must be 15,
> > the number of call nodes in last table must be 20 or less.
> >
> > the number of call elements can be different.
> > eg i have 100 call elements
> > so i have to put in the first table 10 elements,
> > in the tables from 2..6 15 elements
> > and in the last table 15 elements.
> >
> > If i have 106 elements i could put in last table 20 (and 
> make the last
> table
> > complete)
> > elements end still have ones more element,
> > so i have to create one more table with 15 elements and put 
> in the last
> > table the last 6 elements.
> >
> >
> > are there any solutions of that problem???
> >
> > thanks for advise
> >
> > Dmitri
> >
> >  XSL-List info and archive:  
http://www.mulberrytech.com/xsl/xsl-list
>


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

---