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Subject: [xsl] XPath question From: Adam Van Den Hoven <Adam.Hoven@xxxxxxxxxxxx> Date: Thu, 23 Aug 2001 15:42:46 -0700 |
Hey guys: I have two variables defined. The first ($rules) looks something like: <rule state="somestate1"> <attrib name="attributename1">...</attrib> <attrib name="attributename2">...</attrib> <attrib name="attributename3">...</attrib> </rule> <rule> <attrib name="attributename1">...</attrib> <attrib name="attributename2">...</attrib> <attrib name="attributename3">...</attrib> </rule> ... The second ($attribs) looks like: <attrib name="attributename1" state="somestate1">...</attrib> <attrib name="attributename2">...</attrib> <attrib name="attributename3" state="somestate1">...</attrib> ... Now what is all the all the attrib nodes from $rules whose name AND parents state attribute are not present together in $attribs. Given the example above, I want to select: <rule state="somestate1"> <attrib name="attributename1">...</attrib> <!-- Not this --> <attrib name="attributename2">...</attrib> <!-- This --> <attrib name="attributename3">...</attrib> <!-- Not this --> </rule> <rule> <attrib name="attributename1">...</attrib> <!-- This --> <attrib name="attributename2">...</attrib> <!-- Not this --> <attrib name="attributename3">...</attrib> <!-- This --> </rule> Any ideas? Adam van den Hoven Internet Software Developer Blue Zone tel. 604 685 4310 ext. 260 fax 604 685 4391 > Blue Zone makes you interactive. http://www.bluezone.net/ > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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