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Re: [xsl] position within same nodes
Subject: Re: [xsl] position within same nodes From: "Thomas B. Passin" <tpassin@xxxxxxxxxxxx> Date: Thu, 19 Jul 2001 15:52:42 -0400 |
Stylesheet: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <root> <xsl:variable name='meeps' select='//meep'/> <xsl:for-each select='$meeps'> <xsl:value-of select='position()'/>-- </xsl:for-each> </root> </xsl:template> </xsl:stylesheet> Results: <root>1-- 2-- 3-- </root> Cheers, Tom P [Laurence O Garfield] > What is the XPath to get the position of a given node relative to its > siblings of the same name? Eg, > > <blah> > <argh/> > <meep/> > <meep/> > <stuff/> > <meep/> > </blah> > > I'm looking for an XPath statement that would return 1 for the first meep, > 2 for the second, and 3 for the 3rd meep, rather than 2, 3, and 5 (which > is what plain position() returns). XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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Re: [xsl] position within same node, Laurence O Garfield | Thread | Re: [xsl] position within same node, David Carlisle |
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