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Re: [xsl] general string replace problem
Subject: Re: [xsl] general string replace problem From: Jeni Tennison <mail@xxxxxxxxxxxxxxxx> Date: Thu, 7 Jun 2001 18:22:32 +0100 |
Hi Chris, > I'm still having problems using Jeni Tennison's general string > replace template discussed in the FAQ: > http://www.dpawson.co.uk/xsl/stringreplace.html#d44e34517 Oh dear. The problem is that the $search parameter in the replace_strings template is being set through a result tree fragment rather than through the select attribute. That means that when it's used in the predicate later on, it's interpreted as boolean true rather than as a number. If you just change that to: <xsl:param name="search" select="1" /> it should work better. However, I'd amend the template in any case to make it more efficient by passing the node set of foo:search elements rather than an index into that set (which means you're going off and finding it each time): <xsl:template name="replace_strings"> <xsl:param name="input_text" /> <xsl:param name="search" select="document('')/*/foo:string_replacement/foo:search" /> <xsl:variable name="replaced_text"> <xsl:call-template name="replace-substring"> <xsl:with-param name="text" select="$input_text" /> <xsl:with-param name="from" select="$search[1]/foo:find" /> <xsl:with-param name="to" select="$search[1]/foo:replace" /> </xsl:call-template> </xsl:variable> <xsl:choose> <xsl:when test="$search[2]"> <xsl:call-template name="replace_strings"> <xsl:with-param name="input_text" select="$replaced_text" /> <xsl:with-param name="search" select="$search[position() > 1]" /> </xsl:call-template> </xsl:when> <xsl:otherwise> <xsl:value-of select="$replaced_text" /> </xsl:otherwise> </xsl:choose> </xsl:template> I hope that helps, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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