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RE: [xsl] grouping question

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Hi All --

Addendum to my earlier question. This xsl seems to be a good start but I am
having problems with use of "following-sibling". I am operating under the
assumption that I can get the database to tell me how many tracks are in
each product. I am hoping that this will help me.

-Pat Moore-

<?xml version="1.0"?>

<xsl:stylesheet
        version="1.0"
        xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
        xmlns:sql="org.apache.xalan.lib.sql.XConnection"
        xmlns:rioport="com.rioport.util.xsl.XSLUtil"
        xmlns:jDate="java.util.Date"
        extension-element-prefixes="sql rioport jDate" >

    <xsl:output method="xml" indent="yes" />

    <xsl:template match="/" >
        <results>
            <xsl:apply-templates
select="document/row[not(preceding-sibling::row[1]/album = album)]" />
        </results>
    </xsl:template>
    <xsl:template match="row">
        <product>
            <xsl:for-each select="current() | following-sibling::row[1]" >
            <track>
                <xsl:copy-of select="."/>
            </track>
            </xsl:for-each>
        </product>
    </xsl:template>
</xsl:stylesheet>
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> -----Original Message-----
> From: Patrick Moore [mailto:patrickm@xxxxxxxxxxx]
> Sent: Thursday, April 12, 2001 5:45 PM
> To: Xsl List (E-mail)
> Subject: [xsl] grouping question
> 
> 
> Hi there --
> 
> I have looked through the email about grouping withput 
> finding this question
> being answered.
> 
> I am using Xalan sql extension to generate the data that will 
> be processed
> by the xsl stylesheet. Because it is a database query I have 
> constructed the
> query so the results are sorted based on the element that I 
> wish to group
> by. Because this extension lets me look at only one row at a 
> time, and I
> cannot go back, the Mueschean method is not possible. (Or at least not
> prefered).
> 
> I was wondering if anyone had some thoughts on a way I can 
> take advantage of
> the ordering that SQL can do to come up with a simpler 
> method. Some sample
> data:
> 
> <rowset>
> 	
> <row><album>1</album><track_id>1</track_id><artist>Rush</artist></row>
> 	
> <row><album>1</album><track_id>2</track_id><artist>Rush</artist></row>
> 	
> <row><album>2</album><track_id>1</track_id><artist>Rush</artist></row>
> 	
> <row><album>2</album><track_id>2</track_id><artist>Rush</artist></row>
> </rowset>
> 
> As soon as I see the "Album 2" I know that there are no more
> <album>1</album>'s Can I take advantage of this in any manner?
> 
> My preliminary conclusion is no... but I am new enough to xsl 
> to wonder if
> this is indeed the case.
> 
> -Patrick Moore
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 

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