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RE: [xsl] xsl to xsl doing it right
Subject: RE: [xsl] xsl to xsl doing it right From: "Alex Reuter" <areuter@xxxxxxxxxxxxxxxx> Date: Wed, 4 Apr 2001 13:44:09 -0400 |
Hello List, Thanks for all your help. There's something weird going on though in my attempt to implement your suggestions. Here is my namespace aliasing code... <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:alex= "alex-namespace" > <xsl:namespace-alias stylesheet-prefix="xsl" result-prefix="alex"/> <xsl:output method="xsl"/> <xsl:template match="/"> <alex:stylesheet version="1.0"> The xml is processed correctly and everything seems to work properly except....In the output alex is not replaced with xsl. hmmmmm..... Any more suggestions? Thanks again! Alex -----Original Message----- From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Simon Wickes Sent: Tuesday, April 03, 2001 4:26 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] xsl to xsl doing it right At 03:57 PM 4/3/01 -0400, you wrote: >Hello, >I'm trying to output an xsl using xsl and am having a hard time >distinguishing which parts i want the processor to actually process and >which parts are meant to be straight output. <xsl:text> doesn't seem to be >any help and <![CDATA escapes all the brackets making the output useless. >Any suggestions? Doh. OK, the preferred method is to use namespace-alias: <xsl:namespace-alias stylesheet-prefix="simon" result-prefix="xsl"/> and then your xsl looks like this <xsl:template match="/"> <simon:template match="whatever">.... much cleaner. Simon xmlgeek@xxxxxxxxx XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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