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RE: [xsl] and Oracle java classes

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Thanks Steve, this worked perfectly. However, once I deployed the classes
and the stylesheets as stored procedures on the database the code failed to
find the main stylesheet. So - should I put the stylesheets outside the
database, or can it be done with the stylesheets deployed?

Graham Ellis
ACT Financial Systems

*	Tel:       +44 (0) 20 7250 1990
*	Fax:      +44 (0) 20 7553 4713
*	Email:  graham.ellis@xxxxxxxxxxx
*	http://www.actfs.co.uk


> ----------
> From: 	Steve Muench[SMTP:Steve.Muench@xxxxxxxxxx]
> Reply To: 	xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Sent: 	01 March 2001 22:36
> To: 	xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: 	Re: [xsl] <xsl:include> and Oracle java classes
> 
> | I'm writing a Java app that selects data from our Oracle database,
> formats
> | it into XML then uses the Oracle 'XSLStylesheet' and 'XSLProcessor'
> classes
> | to load a stylesheet and transform the XML. 
> | 
> | Unfortunately it fails on the first <xsl:include> - I assume because the
> | main stylesheet is loaded as an InputStream, and the included
> stylesheets
> | are still files on the disk.
> | 
> | Is there a way for the Oracle classes to load stylesheets referenced by
> | <xsl:include>?
> 
> Sure. Load the stylesheet from a resource URL instead of
> as an InputStream. The input stream approach works when
> the stylesheet has no relative stylesheets it needs to
> read, but by using a resource URL, all of the relative
> references are handled for you.
> 
> Here a sample. Assumes the "Sample.xsl" stylesheet and
> the "SampleHelper.xsl" stylesheet which the former
> includes via <xsl:include> are at the the same level
> of directory hierarchy in your CLASSPATH as the current class.
> 
> import oracle.xml.parser.v2.*;
> import java.net.URL;
> public class TransformExample {
>   public static void main( String[] arg ) throws Throwable {
>     DOMParser theParser = new DOMParser();
>     theParser.parse(new java.io.StringReader("<x/>"));
>     XMLDocument source = theParser.getDocument();
>     // Resource "Sample.xsl" does <xsl:include href="SampleHelper.xsl"/>
>     URL url = TransformExample.class.getResource("Sample.xsl");
>     XSLStylesheet transform = new XSLStylesheet(url,url);
>     XSLProcessor proc = new XSLProcessor();
>     proc.processXSL(transform,source,System.out);
>   }
> }
> 
> ______________________________________________________________
> Steve Muench, Lead XML Evangelist & Consulting Product Manager
> BC4J & XSQL Servlet Development Teams, Oracle Rep to XSL WG
> Author "Building Oracle XML Applications", O'Reilly
> http://www.oreilly.com/catalog/orxmlapp/
> 
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 

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