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Re: [xsl] and Oracle java classes
Subject: Re: [xsl] <xsl:include> and Oracle java classes From: "Steve Muench" <Steve.Muench@xxxxxxxxxx> Date: Thu, 1 Mar 2001 14:36:20 -0800 |
| I'm writing a Java app that selects data from our Oracle database, formats | it into XML then uses the Oracle 'XSLStylesheet' and 'XSLProcessor' classes | to load a stylesheet and transform the XML. | | Unfortunately it fails on the first <xsl:include> - I assume because the | main stylesheet is loaded as an InputStream, and the included stylesheets | are still files on the disk. | | Is there a way for the Oracle classes to load stylesheets referenced by | <xsl:include>? Sure. Load the stylesheet from a resource URL instead of as an InputStream. The input stream approach works when the stylesheet has no relative stylesheets it needs to read, but by using a resource URL, all of the relative references are handled for you. Here a sample. Assumes the "Sample.xsl" stylesheet and the "SampleHelper.xsl" stylesheet which the former includes via <xsl:include> are at the the same level of directory hierarchy in your CLASSPATH as the current class. import oracle.xml.parser.v2.*; import java.net.URL; public class TransformExample { public static void main( String[] arg ) throws Throwable { DOMParser theParser = new DOMParser(); theParser.parse(new java.io.StringReader("<x/>")); XMLDocument source = theParser.getDocument(); // Resource "Sample.xsl" does <xsl:include href="SampleHelper.xsl"/> URL url = TransformExample.class.getResource("Sample.xsl"); XSLStylesheet transform = new XSLStylesheet(url,url); XSLProcessor proc = new XSLProcessor(); proc.processXSL(transform,source,System.out); } } ______________________________________________________________ Steve Muench, Lead XML Evangelist & Consulting Product Manager BC4J & XSQL Servlet Development Teams, Oracle Rep to XSL WG Author "Building Oracle XML Applications", O'Reilly http://www.oreilly.com/catalog/orxmlapp/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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