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RE: how to select nodes based on attribute values

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It depends to some extent on whether your 
element_id is defined as type ID in the DTD and 
pick_id is defined as type IDREF in the DTD. 
If they are, this template should work: 

<xsl:template match="b">
<!-- whatever you need to do first -->
 <xsl:apply-templates select="id(@pick_id)"/>
<!-- whatever you need to do later -->
</xsl:template>

The id() function looks for the single element with 
an attribute of type ID that has a value equal to 
what's inside the parens -- thus it's looking for an element
with an attribute that matches the value of pick_id. 

If you're DTD is not set up this way, you can do it
slightly differently.

<xsl:template match="b">
<xsl:variable name="matchto" select="@pick_id"/>
 <xsl:apply-templates select="//*[@element_id=$matchto]"/>
</xsl:template>

This one uses '//*' to search the entire document tree for any
element (the name is not important) that has an element_id
attribute with a value matching pick_id. This method is not 
so efficient :-) And someone else may come up with a better way 
(using keys perhaps?). But this should work. 

Sara
> -----Original Message-----
> From: Archie Russell [mailto:archier@xxxxxxxxxxxxxxx]
> Sent: Thursday, October 05, 2000 3:50 PM
> To: 'XSL-List@xxxxxxxxxxxxxxxx'
> Subject: how to select nodes based on attribute values
> 
> 
> 
> is there a way to select a node based on attribute value 
> matching attribute
> value in another node?
> 
> example
> 
> <?xml version="1.0" encoding="UTF-8"?>
> <xxx>
> <a element_id="1" name="xxx"/>
> <a element_id="2" name="yyy"/>
> <b pick_id="1"/>
> </xxx>
> 
> i want to select all 'a' elements that have element_id 
> matching the value of
> 'b's pick_id (my context is being "in" b)
> i've tried [] but i can't see how to refer to the attributes 
> of "a" and "b"
> simultaneously.
> 
> thanks for any help,
> archie
> 
> archie russell
> doubletwist.com
> 510-587-5766
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 


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