[XSL-LIST Mailing List Archive Home]
[By Thread]
[By Date]
At 12:01 PM 09/26/2000 -0400, Les Howard wrote:
The error makes sense. XSLT variables are in effect ("in scope") only within the block of code in which they're defined. Your stylesheet is structured in part like this:
See? The if-block doesn't know anything about $ValueExists. The second, standalone if-block can't "see into" the if-block which contains the variable's definition; the variable goes out of scope when that if-block closes.
You can sometimes get around the problem by declaring the variable globally -- that is, make the <xsl:variable...> element a top-level element (child of <xsl:stylesheet>). I say sometimes because you can't always get at some information that would be readily available from within a template rule.
Might be better in your case to simply instantiate one template for type="DMA" and a different one for type!="DMA", using those expressions as predicates.
==========================================================
John E. Simpson | "If you were going to
http://www.flixml.org | shoot a mime, would you use
XML Q&A: http://www.xml.com | a silencer?" (Steven Wright)
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Re: newbie variable question
Subject: Re: newbie variable question From: "John E. Simpson" <simpson@xxxxxxxxxxx> Date: Tue, 26 Sep 2000 14:14:53 -0400 |
At 12:01 PM 09/26/2000 -0400, Les Howard wrote:
if there are any grp/type element whose contents are "DMA" I want to print out the value of the associated name in that grp. if there is no grp/type element whose contents is "DMA" I want to print out the values of the description element. [XML:] <area> <grp> <type>MSA</type> <name>foo</type> </grp> <grp> <type>DMA</type> <name>bar</type> </grp> </area> <description>baz</description>
[XSLT:] <xsl:for-each select="area/grp"> <xsl:if test="string(type)='DMA'"> <xsl:value-of select="name"/> <xsl:variable name="ValueExists" select="'True'"/> </xsl:if> </xsl:for-each> <xsl:if test="$ValueExists!="'True'"> <xsl:value-of select="description" /> </xsl:if>
but I keep getting an error:
A reference to variable or parameter 'ValueExists' cannot be resolved. The variable or parameter may not be defined, or it may not be in scope.
The error makes sense. XSLT variables are in effect ("in scope") only within the block of code in which they're defined. Your stylesheet is structured in part like this:
Begin for-each.... If some condition.... Define variable $ValueExists End if End for-each
If some condition.... Do something with $ValueExists End if
See? The if-block doesn't know anything about $ValueExists. The second, standalone if-block can't "see into" the if-block which contains the variable's definition; the variable goes out of scope when that if-block closes.
You can sometimes get around the problem by declaring the variable globally -- that is, make the <xsl:variable...> element a top-level element (child of <xsl:stylesheet>). I say sometimes because you can't always get at some information that would be readily available from within a template rule.
Might be better in your case to simply instantiate one template for type="DMA" and a different one for type!="DMA", using those expressions as predicates.
==========================================================
John E. Simpson | "If you were going to
http://www.flixml.org | shoot a mime, would you use
XML Q&A: http://www.xml.com | a silencer?" (Steven Wright)
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: newbie variable question, David Carlisle | Thread | RE: newbie variable question, Don Bruey |
[no subject], Josh Zeidner | Date | How to search for <, >, etc. in a s, Brian Young |
Month |