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RE: Applying different transformations to every n'th node
Subject: RE: Applying different transformations to every n'th node From: "Selva, Francis" <Francis.Selva@xxxxxxxxxxxxxxx> Date: Wed, 12 Apr 2000 14:44:50 -0700 |
Philip, This is just to get the 4th category to display in a different row.Hope this helps. <xsl:for-each select="//category[position()< 4]"> <xsl:value-of select="."/><xsl:text> </xsl:text> </xsl:for-each> <xsl:for-each select="//category[not(position()<4)]"> <xsl:value-of select="."/><xsl:text> </xsl:text> </xsl:for-each> Change the < sign to = if u want to have a different template for the 4th category. Francis ***************************************************** The woods are lovely,dark and deep. But I have promises to keep, And miles to go before I sleep And miles to go before I sleep. ***************************************************** > I have some xml that goes something like: > > ... > <categories> > <category id="something">Name of Category</category> > <category id="something">Name of Category</category> > <category id="something">Name of Category</category> > ... > </categories> > ... > Basically, what I am trying to do is create a table with 3 > columns, so I > want every fourth column to start a new table row. > > -- > Philip McAllister > Web Developer, ticketingsolutions > pem@xxxxxxxxxxxxxxxxxxxxxx XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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