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Subject: select-distinct in for-each ? From: "Clark C. Evans" <clark.evans@xxxxxxxxxxxxxxxxxxxx> Date: Sun, 3 Oct 1999 02:44:29 -0400 (EDT) |
Hello. I have a hierarchy 3 layers deep, and I'm trying to build a cross-reference of a repeating group in the lowest layer. To do this, I have a <xsl:for-each ... /> with a <xsl:sort ... /> . As you guess, I have duplicates that need to be removed -- I'm looking for a select-distinct. I found this in the FAQ but it partially works: Q: 2.46 How to remove duplicate nodes from a node-set according to content? A: 2.46 - David Carlisle select="reference[not(@name=following::reference/@name)]" will return you a list of reference elements with no two having the same name. Here is my sample data: <a> <b> <c>X</c> </b> <b> <c>X</c> </b> <b> <x>Z</x> </b> </a> <a> <b> <c>X</c> </b> </a> What I want is: X Z What I tried (among many many other things...) <xsl:for-each select="//c[not(text()=following::c/text())]" > <xsl:sort order="ascending" select="." /> <xsl:value-of select="." /><br/> </xsl:for-each> What I get using August 22 version of XT X X Z ... It seems that following:: is grabbing the next sibling, however, if you go up one node and then go back down it does not seem to pick this up. Am I missing anything? Thanks! Clark XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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