[XSL-LIST Mailing List Archive Home]
[By Thread]
[By Date]
how to select the complementary of a child ?
Subject: how to select the complementary of a child ? From: Mathieu Mangeot Lerebours <Mathieu.Mangeot@xxxxxxxxxxxxxx> Date: Tue, 16 Mar 1999 11:56:50 +0100 |
Hello, I'm trying to write an xsl file. Inside a node, I need to select all its children exept one. I'm not able to write this in XSL. Have you got any idea ? The source : <root> <a>...</a> <b>...</b> ................. <z>...</z> </root> The XSL stylesheet: <xsl:template match="root"> <xsl:apply-templates select="a"/> <myns:rest> <xsl:apply-templates select="all-the-children-exept a"/> </myns:rest> </xsl:template> The result: <A>...</A> <myns:rest> <B>...</B> ....... <Z>...</Z> </myns:rest> For : <xsl:apply-templates select="all-the-children-exept a"/> I tried : <xsl:apply-templates select="*[not(a)]"/> <xsl:apply-templates select=".[not(a)]"/> <xsl:apply-templates select="not(a)"/> But I didn't manage to obtain what I want Thank you for your help. -- Mathieu MANGEOT-LEREBOURS | Phone : +33 4 76 61 51 32 Xerox Research Centre Europe | Fax : +33 4 76 61 50 99 6 chemin de Maupertuis | E-mail: Mathieu.Mangeot@xxxxxxx F-38240 Meylan FRANCE | http://www.xrce.xerox.com XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
RE: Problems with LotusXSL., Ed Nixon | Thread | RE: how to select the complementary, Kay Michael |
Re: Problems with LotusXSL., Scott Boag/CAM/Lotus | Date | Problems with LotusXSL., Michel Goossens |
Month |
Keywords