Actually, I just got the following to work (using jclark's XT).  I don't 
know if this is the same problem that you guys were having...but heh, it 
works for me! ;-)

<xsl:template match="item/id">
  <TD><A name="id{../id}">&#160;</A><xsl:process-children/></TD>
</xsl:template>

FWIW,

Glenn

In message <01BE0413.1B19D4C0.ed.nixon@xxxxxxxxxxxxxxxxx> you write:
>Good luck. I posted a similar request earlier this week, i.e., getting 
the
>element type value for the current node and copying it into an attribute 
value
 
>for the result. I didn't get a single nibble. Reading around and breaking 
my
>brain on the specification some more, I don't think this is possible at 
the
>moment. It seems to be possible to get an attribute value and place it in 
a new
>output side attribute value but not the tag name/element type. I'd love 
to be
>proven wrong.
>
>	...edN
>
>-----Original Message-----
>From:	Glenn R. Kronschnabl [SMTP:grk@xxxxxxxxxxxxxxxx]
>Sent:	Friday, October 30, 1998 1:24 PM
>To:	xsl-list@xxxxxxxxxxxxxxxx
>Subject:	Ugh!  accessing current value in <A name= in template
>
>I'm just not getting it:
>
>I want to use the value of the tag as part of a <A name=
>but I can't figure it out.  I tried this (and variations
>but nothing works).
>
><xsl:template match="item/id">
>  <TD><A name="{id}">&#160;</A><xsl:process-children/></TD>
></xsl:template>
>
>To say it another way,  I have a xml file that looks something like:
>
><item>
>  <id>1</id>
>  etc.
>
>and I am building a table and I want the output id column to look like:
>
><TR>
>  <TD><A name="id1">&#160;</A>1</TD>
>                 ^            ^
>                 |            |   both are the tag value
></TR>
>
>How?  I feel like this should be simple...
>


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