[oXygen-user] Syntax problem with xslt 'contains' text()
G. Ken Holman
gkholman at CraneSoftwrights.com
Tue Jun 12 12:56:09 CDT 2012
At 2012-06-12 18:44 +0100, McGibbney, Lewis John wrote:
>In particular I wish to grab every occurrence of an <xs:element>
>where the substitutionGroup value is equal to "ifc:IfcBuildingElement"
>I've been using the following xsl code and it is not working.
><?xml version="1.0" encoding="UTF-8"?>
> exclude-result-prefixes="xs xd"
> <xsl:output method="xml" omit-xml-declaration="yes" indent="yes"/>
> <xsl:strip-space elements="*"/>
> <xsl:template name="main" match="/">
> <xsl:for-each select="xs:schema/xs:element">
> <xsl:if test="@substitutionGroup[contains(text(),
Above you are asking to compare a text node with the child element
named IfcBuildingElement in the namespace associated with the ifc
prefix. Two problems: attribute nodes never contain text node
children, and you are asking for the content of a child element
rather than simple text.
Do you not just want the following?
But up above you say "is equal to" so that means you could probably
live with a simple string comparison (which does nothing about string
Note this does not accommodate namespsce prefix dereferencing ... you
are just checking for a string. Which is what I think you are asking for.
> <xsl:value-of select="xs:schema/xs:element"/>
At this point you are addressing an xs:schema child of the previously
selected xs:element, which is also wrong ... I suspect you don't want
to walk away from the element you just tested.
Do you want the element's name? You are asking for the string value
of the element's descendants and I don't think you want that. That
will always just be white space in the schema.
Did you want to copy the element declarations? If so you could have:
>It would be great if someone could point out to me either the
>incorrect syntax or the absence of the correct configuration.
I hope this helps. If you could find some basic instruction on XPath
nodes and node addressing, it would help you to understand where you
. . . . . . . . . Ken
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