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[xsl] Following-sibling - question


Subject: [xsl] Following-sibling - question
From: "a kusa akusa8@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Wed, 6 Jan 2016 14:31:23 -0000

Hello:

I am trying to write some code to find the next X number of following
sibling elements and I am a little stuck.

My input XML file is a table:

<table>

<tbody>
<row>

<entry>1</entry>
</entry>2</entry>

</row>

<row>
<entry>3</entry>
</entry>2</entry>
</row>

<row>
<entry>4</entry>
</entry>2</entry>
</row>

<row>
<entry>5</entry>
</entry>2</entry>
</entry>2</entry>
</row>

<row>
<entry>6</entry>
</row>


</tbody>


</table>


My desired output is:

<table>

<tbody>
<row>

<entry>1</entry>
</entry>2</entry>

</row>

<row>
<entry>want entry here - 1.1</entry>
<entry>3</entry>
</entry>2</entry>
</row>

<row>
<entry>4</entry>
<entry>want an entry here - 3.1 </entry>
</entry>7</entry>
</row>

<row>
<entry>5</entry>
</entry>2</entry>
</entry>2</entry>
<entry>want an entry here - 7.1</entry>
</row>

<row>
<entry>6</entry>
</row>


</tbody>


</table>


So, I want to write logic to say that for the next n where n=3 in this
example -  rows, add an entry element

I tried to calculate the next n rows based on current(), but it is not
working. Any suggestion is appreciated. Thank you in advance for your
help.


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