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Re: [xsl] Need Math Help: How to Convert Proportional Column Widths to Real Values?


Subject: Re: [xsl] Need Math Help: How to Convert Proportional Column Widths to Real Values?
From: "a kusa akusa8@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Tue, 29 Dec 2015 18:18:33 -0000

Hello:

I was looking to do something similar and found this question. In my
case, I don't have the total table column width always. So, if I have
a mixed col width values of 1.38,1.38.1*,1.38, how can I find the real
value for 1*?

Thanks in advance for all suggestions.



On Fri, Mar 7, 2014 at 6:10 PM, Liam R E Quin <liam@xxxxxx> wrote:
> On Fri, 2014-03-07 at 17:51 -0600, Eliot Kimber wrote:
>
>> For example, say that I have two proportional columns of width "1*" and
>> "1.39*" and the available width is 240pt.
>>
>> How do I determine fraction of 240 each of these proportions get?
>
> 1. add up the proportional values; call that Peter.
> 2. subtract any fixed-width columns from the available width to get
>    whatever remaineth; call that Wendy.
> 3. each column has width in proportion, so that a column with width 1.38
>    has actual width of Wendy C 1.38 divided by Peter.
> (you could call them ProportionalTotal and WidthAvailable rather than
> Peter and Wendy if you wanted I suppose.)
>
> --
> Liam Quin - XML Activity Lead, W3C, http://www.w3.org/People/Quin/
> Pictures from old books: http://fromoldbooks.org/
> Ankh: irc.sorcery.net irc.gnome.org freenode/#xml


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