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[xsl] Get children and text, excluding a child


Subject: [xsl] Get children and text, excluding a child
From: "Rick Quatro rick@xxxxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Fri, 12 Jun 2015 20:44:15 -0000

Hello,

Here is my input xml:

<?xml version="1.0"?>
<root>
  <span><number>9.3</number> <code>protected</code> members</span>
  <span><number>9.4</number> miscellaneous members.</span>
</root>

Here is the desired output:

<?xml version="1.0"?>
<root>
  <span> <code>protected</code> members</span>
  <span> miscellaneous members.</span>
</root>

I want to output all of the elements and text of the original <span> element,
but without the <number> element. I am using this for my xsl:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:xs="http://www.w3.org/2001/XMLSchema"
    exclude-result-prefixes="xs"
    version="2.0">

    <xsl:output method="xml" indent="yes"/>

    <xsl:template match="/root">
        <root>
            <xsl:for-each select="span">
                <xsl:copy-of select="descendant::*[not(self::number)]"/>
            </xsl:for-each>
        </root>
    </xsl:template>

</xsl:stylesheet>

This is my current (incorrect) output:

<?xml version="1.0" encoding="UTF-8"?>
<root>
   <code>protected</code>
</root>

Any help or pointers would be appreciated. Thanks.

Rick Quatro
Carmen Publishing Inc.
585-366-4017
rick@xxxxxxxxxxxxxxx


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