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Re: [xsl] Increasing sequence ?


Subject: Re: [xsl] Increasing sequence ?
From: "Leo Studer leo.studer@xxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Fri, 27 Mar 2015 09:36:27 -0000

Dimitre

thanks, this is amazing. With Saxon EE in Oxygen 16.1 I get stack overflow
with 10000 ;-).
Can you compare the time with this solution?
declare namespace my = "my:my";
declare function my:increasing2($seq as xs:double*)as xs:boolean
{every $v in 1 to (count($seq)-1) satisfies ($seq[$v] lt $seq[$v+1])};
let $v:=(1 to 1000000) return (my:increasing2($v))

Cheers
Leo

> On 27.03.2015, at 05:24, Dimitre Novatchev dnovatchev@xxxxxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
>
> Hi Leo,
>
> I ran this with BaseX 7.8.2:
>
> declare namespace my = "my:my";
> declare function my:increasing($seq as xs:double*) as xs:boolean
> {empty($seq[2])
> or
>  $seq[1] lt $seq[2]  and  my:increasing(subsequence($seq, 2))
> };
> let $v:=(1 to 10000)
>  return my:increasing($v)
>
>
> And here is the result (do note this below: - marking as ***tail
> call***: my:increasing(fn:subsequence($seq_0, 2))  )
>
> Total Time: 3.74ms (for 100 000 - long sequence the time was 17.77ms,
> for 1 000 000 - long sequence the time was 207.56ms)


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