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[xsl] streaming identity transformation

Subject: [xsl] streaming identity transformation
From: "Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Sun, 25 Jan 2015 15:14:09 -0000

I am wondering how one would write the identity transformation template

<xsl:template match="@* | node()">
    <xsl:apply-templates select="@* | node()"/>

in an XSLT 3.0 stylesheet supposed to work with streaming. The section http://www.w3.org/TR/xslt-30/#built-in-templates-shallow-copy in the XSLT 3.0 specification has a template

<xsl:template match="." mode="M">
  <xsl:copy validation="preserve">
    <xsl:apply-templates select="@*" mode="M"/>
    <xsl:apply-templates select="node()" mode="M"/>

and explains "A further reason for choosing this form is for streamability: this formulation is guaranteed-streamable".

However, when I try

<xsl:stylesheet version="3.0"

<xsl:mode streamable="yes"/>

<xsl:template match=".">
  <xsl:copy validation="preserve">
    <xsl:apply-templates select="@*"/>
    <xsl:apply-templates select="node()"/>


with Saxon 9.6 EE I get a compilation error saying:

Error at xsl:template on line 8 column 25 of test2015012505.xsl:
XTSE3430: Template rule is declared streamable but it does not satisfy the streamability rules.
* In a streaming apply-templates instruction, the select expression cannot select
ancestors or attributes (that is, it must not have climbing posture)

So how would one write a template doing a shallow copy and then processing any attribute and child nodes in a streaming way?

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