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Re: [xsl] Boolean Value of a Sequence of Booleans

Subject: Re: [xsl] Boolean Value of a Sequence of Booleans
From: "Dimitre Novatchev dnovatchev@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Fri, 5 Dec 2014 21:11:17 -0000

I think you could just use:


In XPath 3.0 one could use:

 fold-right($seq, true(), function(x as xs:boolean, y as xs:boolean)
as xs:boolean {x and y})

and in XSLT 2.0 one could use the FXSL function f:foldr() and f:and()
in a similar way:


And even in XSLT 1.0 one can use the FXSL function f:some-true() :

I believe that (at least in Haskell) foldr() is defined in such a way
that it will short-circuit.


On Fri, Dec 5, 2014 at 12:39 PM, Eliot Kimber ekimber@xxxxxxxxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
> I think I must be forgetting something fundamental, but I'm not figuring
> out how to do something that should be fundamental, I think.
> Using XSLT2, I'm examining all the items in a key() map to see if any
> entries in the map have more than 1 item. I'm doing this by iterating over
> the keys. I'm then producing a boolean for each iteration and capturing
> the sequence of booleans in a variable.
> My thinking was that I could then just AND the sequence to determine if
> any of the items had more than 1 item. But I see that boolean() and not()
> don't operate on sequences of booleans. Hmph.
> I realize thinking about it now that I can only put true() items in my
> sequence and then just check the first one.
> But my question still remains: is there a built-in way to apply boolean
> operators to a sequence of booleans or would I need to write my own
> function? Obviously, if I was writing my own function I'd just use
> recursion to walk the sequence, which would allow early termination for
> and() and or().
> Have I missed something obvious or not so obvious? I am I just thinking
> about this particular problem the wrong way?
> Thanks,
> Eliot
> bbbbb
> Eliot Kimber, Owner
> Contrext, LLC
> http://contrext.com

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