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Re: [xsl] Saxon unix script command line not finding stylesheet even though it exists


Subject: Re: [xsl] Saxon unix script command line not finding stylesheet even though it exists
From: "Wolfgang Laun wolfgang.laun@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Fri, 14 Nov 2014 16:12:45 -0000

On 13 November 2014 22:51, Catherine Wilbur cwilbur@xxxxxxxxxxx <
xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

> What would cause the following error to occur
>
> Stylesheet file  -xsl:/usr/local/finesrv/erp/jdedwardsoneworld/cron/
> *LibrXML2CSV_stylesheet.xsl* does not exist
>
> when I call the Saxon processor.  The stylesheet  file actually exists in
> the directory specified.
>
> Is it because I have not done the following to my stylesheet as specified
> on listserv yesterday?
>         $ chmod ugo+x LibrXML2CSV_stylesheet.xsl
>

The chmod was suggested to be applied to a shell script, not the xsl file.

To debug, use lines

   echo $FinesrvCronDir/LibrXML2CSV_stylesheet.xsl
   ls -l $FinesrvCronDir/LibrXML2CSV_stylesheet.xsl

preceding the invocation of the XSL transformation and see what this
produces: it should show the correct full pathname and display all file
attributes.

It is possible that the user executing the transformation does not have
execute permission on one of the directories on the path leading to the xsl
file. Then saxon would report

   Stylesheet file /foo/bar/blech.xsl does not exist

"Execute permission" for a directory means that you can cd there and access
files in or below that directory. Here's the ls -ld for my /tmp directory:

   $ ls -ld /tmp
   drwxrwxrwt 11 root root 4096 Nov 14 17:04 /tmp

The three 'x' indicate "execute permission" for the owner (root), users of
group root and all other users, respectively.

HTH
-W


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