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[xsl] Re: XSLT 3.0: What is the default visibility of a package component inside the declaring package ?


Subject: [xsl] Re: XSLT 3.0: What is the default visibility of a package component inside the declaring package ?
From: "Michael Kay mike@xxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Sun, 2 Nov 2014 17:59:06 -0000

The rules are given here:

http://www.w3.org/TR/xslt-30/#element-expose

The visibility depends on both the visibility attribute of the component, and
the rules in the package's xsl:expose declarations. If neither apply, the
default visibility is private.

The visibility of a component affects whether it can be used in a different
package. Components can always be used within the package in which they are
declared.

Michael Kay
Saxonica
mike@xxxxxxxxxxxx
+44 (0) 118 946 5893




On 2 Nov 2014, at 17:09, Dimitre Novatchev <dnovatchev@xxxxxxxxx> wrote:

> What is the default visibility of a package component inside the
> declaring package, if the component has no "visibility" attribute
> specified on its declaration?
>
> I believe that the default visibility should be "public", however I
> couldn't find any statement about this in the latest XSLT 3.0
> specification.
>
> So, could someone confirm my guess, and/or point the text in the Spec
> that explains this?
>
> If there isn't really such definition, I believe it needs to be added
> to the specification.
>
> --
> Cheers,
> Dimitre Novatchev


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