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Re: [xsl] Select item from schedule based on date in XPath 1.0

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> On Jul 30, 2014, at 10:00 AM, "Philipp Kursawe phil.kursawe@xxxxxxxxx"
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
>
> Hello all,
>
> I have this XML
>
> <daily>
> <item startTime="2014-07-26T10:00:00.000Z">
> <item startTime="2014-07-26T11:00:00.000Z">
> <item startTime="2014-07-26T12:00:00.000Z">
> <item startTime="2014-07-26T13:00:00.000Z">
> </daily>
>
> I want to select the item for a specific time, ie for 11:15 it should select
the second item.
>
> I am using XPath 1.0 so for the date comparison itself I use this trick:
> number(translate(@startTime, "-T:.Z", ""))
> to get a number representation for the startTime attibute.
>
> My trouble is now with finding the next sibling to compare its startTime (in
my example the item that starts at 12:00) Basically my expression in pseudo
xpath would be
> item[@startTime >= time and next-sibling[@startTime < time]
>
> Thanks for any hints!
> Phil
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I don't know if this is a place for this type of querying.

E-S4L

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