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[xsl] How to show explicitly the implicit sequence constructor?


Subject: [xsl] How to show explicitly the implicit sequence constructor?
From: "Costello, Roger L." <costello@xxxxxxxxx>
Date: Sat, 29 Mar 2014 09:28:02 +0000

Hi Folks,

In the following template rule is an implicit sequence constructor. The
sequence constructor expresses this: "Show the value of Title, then show the
value of Author."

    <xsl:template match="Book">
        <xsl:value-of select="Title" />
        <xsl:value-of select="Author" />
    </xsl:template>

Is there a way to explicitly show the sequence constructor?

For example, this would be a neat way to explicitly show the sequence
constructor:

    <xsl:template match="Book">
        <xsl:sequence>
            <xsl:value-of select="Title" />
            <xsl:value-of select="Author" />
        </xsl:sequence>
    </xsl:template>

Unfortunately that is not legal.

Is there a way to explicitly show the sequence constructor?

/Roger


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