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Re: [xsl] Only child test

Subject: Re: [xsl] Only child test
From: Andre Cusson <ac@xxxxxxxxxxxxx>
Date: Thu, 10 Oct 2013 10:34:44 -0400

Wouldn't "last() eq 1" or "last() gt 1" be both the fastest and clearest?


This is the  first expression I thought about -- then saw that
PQQP5QP;P0P2 P!P5P4P>P2 has already offered it.


On Wed, Oct 9, 2013 at 9:38 PM, Karl Stubsjoen <kstubs@xxxxxxxxx> wrote:
Just curious how other's might approach a test to determine if the
current node is *not* an only child. This works fine but it feels a
little heavy to me.  Thoughts?

                 <xsl:if test="(count(preceding-sibling::*) +
count(following-sibling::*)) &gt; 1">

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