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At 2013-10-09 21:38 -0700, you wrote:
I think you need "... >0" in your test above to know that the current element has no siblings.
But if you know your current node is an element you could ask:
test="count(../*)!=1"
... which would return true if the current element is not an only child element.
I hope this helps.
. . . . . . Ken
Re: [xsl] Only child test
Subject: Re: [xsl] Only child test From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx> Date: Thu, 10 Oct 2013 00:45:00 -0400 |
At 2013-10-09 21:38 -0700, you wrote:
Just curious how other's might approach a test to determine if the current node is *not* an only child. This works fine but it feels a little heavy to me. Thoughts?
<xsl:if test="(count(preceding-sibling::*) + count(following-sibling::*)) > 1"> <hr/> </xsl:if>
I think you need "... >0" in your test above to know that the current element has no siblings.
But if you know your current node is an element you could ask:
test="count(../*)!=1"
... which would return true if the current element is not an only child element.
I hope this helps.
. . . . . . Ken
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