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Re: [xsl] Replacing \U+00A0


Subject: Re: [xsl] Replacing \U+00A0
From: Wolfgang Laun <wolfgang.laun@xxxxxxxxx>
Date: Sat, 24 Aug 2013 07:39:25 +0200

Or use the simpler '#xA0'
-W

On 23/08/2013, Martin Holmes <mholmes@xxxxxxx> wrote:
> The replace() function uses a regular expression pattern, so I think
> you'll need to escape the backslash:
>
> '\\U00A0'
>
> Cheers,
> Martin
>
> On 13-08-23 12:25 PM, Mario Madunic wrote:
>> Hi,
>>
>> Having a problem replacing the following string in some XML, \U+00A0. It
>> is appearing as is in the XML. Example: <p>This para\U+00A0contains.</p>
>>
>> Using Saxon HE 9.5.0.1J.
>>
>> Tried the following:
>> <xsl:value-of select="if (contains(., '\U+00A0')) then replace(.,
>> '\U+00A0', ' ') else ." />. Am able to find the string in question (using
>> contains()) but am unable to replace it.
>>
>> Any insight and help will be appreciated.
>>
>> Thanks
>>
>> Mario Madunic | Software Developer | AeroInfo Systems, A Boeing Company |
>> mario.madunic@xxxxxxxxxxxx | #200-13575 Commerce Parkway | Richmond, BC,
>> V6V 2L1, Canada | www.aeroinfo.com | www.boeing.com
>>
>>
>
> --
> Martin Holmes
> University of Victoria Humanities Computing and Media Centre
> (mholmes@xxxxxxx)


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