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Re: [xsl] format-number() issue

Subject: Re: [xsl] format-number() issue
From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>
Date: Fri, 16 Aug 2013 10:15:08 -0400

At 2013-08-16 10:11 -0400, Nathan Tallman wrote:
I'm trying to use format-number like this:

<xsl:variable name="unitid" select="lower-case(/ead/archdesc/did/unitid)"/>
<xsl:variable name="number" select="substring($unitid, 3)" />
<xsl:value-of select="format-number($number, '0000')"/>

I've seen many examples online of using a variable in the first spot
with format-number, but I keep getting a validation error, "Required
item type of first argument of format-number() is numeric; supplied
value has item type xs:string."

I've tried sticking as="xs:integer" in <xsl:variable  name="number">
and adding the xs namespace, but then I get this error, "Required item
type of value of variable $number is xs:integer; supplied value has
item type xs:string".

It surprises me that that didn't work.

I can't make $unitid an integer, as it has alpha
characters in it (which I remove in $number).

Can someone point out my errors or give me a hint?

You could cast the argument to an acceptable type:

format-number( xs:integer($number), '0000' )

... or if you aren't dealing with integers:

format-number( xs:double($number), '0000' )

I hope this helps.

. . . . . . . . Ken

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